document.write( "Question 342838: Jack is twice as old as Lacy. In 3 years the sum of their ages will be 54. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #245365 by stanbon(75887)\"\" \"About 
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Jack is twice as old as Lacy.
\n" ); document.write( "J = 2L
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\n" ); document.write( "In 3 years the sum of their ages will be 54.
\n" ); document.write( "(J+3)+(L+3) = 54
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\n" ); document.write( "How old are they now?
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\n" ); document.write( "Substitute for J and solve for \"L\":
\n" ); document.write( "(2L+3)+(L+3) = 54
\n" ); document.write( "3L + 6 = 54
\n" ); document.write( "3L = 48
\n" ); document.write( "L = 16 (Lacy's age now)
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\n" ); document.write( "Since J=2L, J = 32 (Jack's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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