document.write( "Question 342838: Jack is twice as old as Lacy. In 3 years the sum of their ages will be 54. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #245365 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Jack is twice as old as Lacy. \n" ); document.write( "J = 2L \n" ); document.write( "--------- \n" ); document.write( "In 3 years the sum of their ages will be 54. \n" ); document.write( "(J+3)+(L+3) = 54 \n" ); document.write( "------------------------ \n" ); document.write( "How old are they now? \n" ); document.write( "----- \n" ); document.write( "Substitute for J and solve for \"L\": \n" ); document.write( "(2L+3)+(L+3) = 54 \n" ); document.write( "3L + 6 = 54 \n" ); document.write( "3L = 48 \n" ); document.write( "L = 16 (Lacy's age now) \n" ); document.write( "--- \n" ); document.write( "Since J=2L, J = 32 (Jack's age now) \n" ); document.write( "========================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |