document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=342847>Question 342847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 4 factories in a group of 20 factories in a community are violating environmental regulations and 6 are randomly selected for inspection, what is the probability that none of the violators will be selected?\r<BR>\n" );
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document.write( "I did: 6/20= 0.3% no violators will be selected\r<BR>\n" );
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document.write( "Is this correct?<BR>\n" );
document.write( "Do I leave it as a percentage? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245362 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 4 factories in a group of 20 factories in a community are violating environmental regulations and 6 are randomly selected for inspection, what is the probability that none of the violators will be selected? <BR>\n" );
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document.write( "16 of the 20 factories are not violators.<BR>\n" );
document.write( "P(not violator) = 16/20 = 4/5 = 0.8<BR>\n" );
document.write( "P(violator) = 0.2<BR>\n" );
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document.write( "Binomial Problem with n= 6 and p = 0.8<BR>\n" );
document.write( "P(x=6 non-violators) = 6C6(0.8)^6(0.2)^0 = 0.8^6 = 0.2621<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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