document.write( "Question 342841: The lenght of a rectangle is 5 inches more than the width. The perimeter is 34 inches. Find the lenght and the width? \n" ); document.write( "
Algebra.Com's Answer #245355 by mananth(16946)\"\" \"About 
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width be x
\n" ); document.write( "length = x+5
\n" ); document.write( "..
\n" ); document.write( "Perimeter P = 2*(L+W)
\n" ); document.write( "2(x+x+5)=34
\n" ); document.write( "4x+10=34
\n" ); document.write( "divide by 2
\n" ); document.write( "2x+5=17
\n" ); document.write( "-5
\n" ); document.write( "2x= 17-5
\n" ); document.write( "2x=12
\n" ); document.write( "x=6in
\n" ); document.write( "length = x+5= 6+5 =11 in
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