document.write( "Question 342799: the perimeter of a rectangle is 52 ft. the length of the rectangle is 10 ft longer than the width. find the demesions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #245340 by user_dude2008(1862)![]() ![]() ![]() You can put this solution on YOUR website! 52=2(w+10)+2w\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "52=2w+20+2w\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "52-20=2w+2w\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "32=4w\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "w=8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "width = 8, length = 18 \n" ); document.write( " |