document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=342767>Question 342767</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really need help for this question here before tomorrow. Here's what it is asking: Find the measure of an angle if the measure of its complement is one third the measure of its supplement. If I could get a translation of sorts, then I will also be able to answer a couple more question, which I unfortunately need for tomorrow.<BR>\n" );
document.write( "Thanks to whoever can help me!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245313 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the measure of an angle if the measure of its complement is one third the measure of its supplement.<BR>\n" );
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document.write( "A = the angle<BR>\n" );
document.write( "90 - A = its complement = c<BR>\n" );
document.write( "180 - A = its supplement = s<BR>\n" );
document.write( "c = s/3<BR>\n" );
document.write( "90-A = (180-A)/3<BR>\n" );
document.write( "270 - 3A = 180-A<BR>\n" );
document.write( "A = 45º\r<BR>\n" );
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