document.write( "Question 342739: How many liters of a 20% alcohol solution should Maria
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document.write( "mix with 50 liters of a 60% alcohol solution to obtain a
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document.write( "30% solution? \n" );
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Algebra.Com's Answer #245309 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of a 20% alcohol solution should Maria \n" ); document.write( "mix with 50 liters of a 60% alcohol solution to obtain \n" ); document.write( "a 30% solution? \n" ); document.write( "--------------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.20x + 0.60*50 = 0.30(x+50) \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "20x + 60*50 = 30x + 30*50 \n" ); document.write( "10x = 30*50 \n" ); document.write( "x = 150 liters (amt. of 20% solution needed in the mixture) \n" ); document.write( "--- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " \n" ); document.write( " |