document.write( "Question 342739: How many liters of a 20% alcohol solution should Maria
\n" ); document.write( "mix with 50 liters of a 60% alcohol solution to obtain a
\n" ); document.write( "30% solution?
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Algebra.Com's Answer #245309 by stanbon(75887)\"\" \"About 
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How many liters of a 20% alcohol solution should Maria
\n" ); document.write( "mix with 50 liters of a 60% alcohol solution to obtain
\n" ); document.write( "a 30% solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.20x + 0.60*50 = 0.30(x+50)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "20x + 60*50 = 30x + 30*50
\n" ); document.write( "10x = 30*50
\n" ); document.write( "x = 150 liters (amt. of 20% solution needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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