document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39005>Question 39005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a math exam tomorrow and i can not figure out this problem!! can you help? (it is not from a text book. . . she made our review up)<BR>\n" );
document.write( "Log(6)5= Log(6)(2x+1)- log(6)(3x+4)<BR>\n" );
document.write( "* the parenthesis are the bases! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24525 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay from<BR>\n" );
document.write( "log(6)5 = log(6)(2x+1) - log(6)(3x+4)<BR>\n" );
document.write( "we combine to get<BR>\n" );
document.write( "log(6)5 = log(6)[(2x+1) / (3x+4)] and then eliminating logs we have<BR>\n" );
document.write( "(2x+1) / (3x+4) = 5<BR>\n" );
document.write( "15x + 20 = 2x + 1<BR>\n" );
document.write( "13x = -19<BR>\n" );
document.write( "x = -19/13<BR>\n" );
document.write( "but since that would make log(6)(2x+1) the log of a negative, the answer is NO SOLUTION...poor problem construction actually... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );