document.write( "Question 342530: a=b
\n" ); document.write( "ab=b2
\n" ); document.write( "ab-a2 = b2-a2
\n" ); document.write( "a(b-a)=(b+a)(b-a)
\n" ); document.write( "a=b+a
\n" ); document.write( "a=a+a
\n" ); document.write( "a=2a
\n" ); document.write( "1=2 \r
\n" ); document.write( "\n" ); document.write( "My teacher says that 1=2 but this problem is NOT correct, can you explain to my why it will not work?
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Algebra.Com's Answer #245190 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since you're assuming that a=b, this means that \"b-a=a-a=0\". So when you divide both sides by \"b-a\", you're basically dividing by zero (which is NOT allowed). \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Jim
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