document.write( "Question 342509: 3(2z-1)=6z+5 \n" ); document.write( "
Algebra.Com's Answer #245172 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"3%282z-1%29=6z%2B5\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"6z-3=6z%2B5\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"6z=6z%2B5%2B3\" Add \"3\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"6z-6z=5%2B3\" Subtract \"6z\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0z=5%2B3\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"0z=8\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"0=8\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "Since this equation is NEVER true for any z value, this means that there are no solutions.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider a making a donation at my website. Thanks.\r
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\n" ); document.write( "\n" ); document.write( "Jim
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