document.write( "Question 342259: The relationship between the number of calculators x that
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document.write( "a company can sell per month and the price of each calculator p is given by
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document.write( "x = 1700 - 100p. Find the price at which a calculator should be sold to produce a
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document.write( "monthly revenue of $7000. (Hint: Revenue = xp.) \n" );
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Algebra.Com's Answer #245100 by jsmallt9(3758) ![]() You can put this solution on YOUR website! With \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "we have a system of two equations with two variables. Since the second equation is of degree 2 (because of the x*p term), we will use the Substitution Method. (With second degree equations other methods are often either not possible or not practical.) \n" ); document.write( "Since we already have the first equation solved for x, we will use that and substitute into the second equation: \n" ); document.write( " \n" ); document.write( "To solve this we will start by simplifying: \n" ); document.write( " \n" ); document.write( "We can simplify the equation by dividing both sides by 100: \n" ); document.write( " \n" ); document.write( "Now we can factor (or use the Quadratic Formula): \n" ); document.write( " \n" ); document.write( "From the Zero Product property we know that: \n" ); document.write( " \n" ); document.write( "solving these we get: \n" ); document.write( "p = 7 or p = 10 \n" ); document.write( "Now we find the x for each of these p's. We'll use the first equation and substitute in the value for p: \n" ); document.write( "For p = 7: \n" ); document.write( " \n" ); document.write( "For p = 10: \n" ); document.write( " \n" ); document.write( "So we have two solutions which generate $7000 revenue: \n" ); document.write( "When the price is $7, 1000 calculators will be sold. \n" ); document.write( "When the price is $10, 700 calculators will be sold. \n" ); document.write( "If it is cheaper to build 700 calculators than it would be to build 1000 calculators, the greatest profit would come from making 700 calculators and selling them for $10 each.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |