document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=342409>Question 342409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thomas collects dimes and quarters in his change jar. If he has 4 more dimes than quarters, and the total amount of money in the jar is $30.50, find the number of each type of coin in the jar. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245094 by </B><A HREF=/tutors/aboutme.mpl?userid=kcanil08><B>kcanil08(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kcanil08><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kcanil08><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> no. of dimes=x<BR>\n" );
document.write( "no. of quarters = y\r<BR>\n" );
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document.write( "from 1st condition,<BR>\n" );
document.write( "x*.10+y*.25=30.50\r<BR>\n" );
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document.write( "from 2nd condition,<BR>\n" );
document.write( "x-4=y\r<BR>\n" );
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document.write( "substitution value of y in 1st equation,\r<BR>\n" );
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document.write( "x*10+(x-4)*25=30.50<BR>\n" );
document.write( "solving we get <BR>\n" );
document.write( "no. of dimes :90<BR>\n" );
document.write( "no.of quater: 86 </SPAN>\n" );
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