document.write( "Question 342391: Please help me solve this: \r
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document.write( "The perimeter of a rectangle is 24 centimeters. The length of the rectangle is four more than the width. What is the length of the rectangle?\r
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document.write( "4x+x=24?\r
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document.write( "I having difficulty with this subject.\r
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document.write( "Lisa \n" );
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Algebra.Com's Answer #245060 by MathTherapy(10858) You can put this solution on YOUR website! The perimeter of a rectangle is 24 centimeters. The length of the rectangle is four more than the width. What is the length of the rectangle?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the length of the rectangle be L\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then its width = L - 4, since the length of the rectangle is four more than the width\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter of any rectangle = 2L + 2W. Since the length and width of this rectangle = L and L - 4, respectively, and since its perimeter is 24 centimeters, then we can say that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2L + 2(L - 4) = 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2L + 2L - 8 = 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4L = 24 + 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4L = 32\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L, or length = |