document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=342367>Question 342367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A box contains two red chips and three white chips.  Let X denote the number of draws until a red chip is selected.<BR>\n" );
document.write( "(1)  Find the discrete pdf for X if the chips are drawn at random, with replacement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #245056 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=245056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since the drawing is with replacement <BR>\n" );
document.write( "the probability of selecting a red is constant.<BR>\n" );
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document.write( "Let prob(red)=p=2/5 , let prob(white)=1-p=3/5<BR>\n" );
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document.write( "If X represent number of draws until the first success, ie selecting the first red,<BR>\n" );
document.write( "then the pdf of X implies that there will be X-1 failures and the last one will be a success\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28X=x%29=%281-p%29%5E%28x-1%29p ALIGN=MIDDLE  ALT=\"P%28X=x%29=%281-p%29%5E%28x-1%29p\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283%2F5%29%5E%28x-1%29%282%2F5%29 ALIGN=MIDDLE  ALT=\"%283%2F5%29%5E%28x-1%29%282%2F5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > for x>0<BR>\n" );
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document.write( "this is the geometric probability distribution, since is sequence increases geometrically </SPAN>\n" );
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