document.write( "Question 342207: Sixty grams of an alloy that contains less that 15% gold is melted together with 45 g of an alloy that is 20% gold. What do you know about the amount of gold in the resulting alloy? \n" ); document.write( "
Algebra.Com's Answer #245042 by nyc_function(2741) You can put this solution on YOUR website! Call the amount of gold in the first alloy x \n" ); document.write( "Sixty grams of an alloy that contains less that 15% gold \n" ); document.write( "x <15% * 60 \n" ); document.write( "x <15/100 * 60 = 15/10 * 6 = 3/2 * 6 = 9 \n" ); document.write( "x<9grams\r \n" ); document.write( "\n" ); document.write( "Call the amount of gold in the second alloy y \n" ); document.write( "45 g of an alloy that is 20% gold \n" ); document.write( "y < 20/100 * 40 \n" ); document.write( "y<8 \n" ); document.write( "the amount of gold in the resulting alloy is the sum of the 2 so it is \n" ); document.write( "(x+y) <9 + 8 \n" ); document.write( "(x+y)<17g\r \n" ); document.write( "\n" ); document.write( "If you want to put this in percentage terms, we have a total weight of 60 + 45 = 105g \n" ); document.write( "%gold <17/105 \n" ); document.write( "%gold<16% \n" ); document.write( " \n" ); document.write( " |