document.write( "Question 342339: Ava rode her bike from her house to her friends house averaging 16 km per hour. It turned dark so her friend drove her home at a rate of 80 km per hour. If Ava's total traveling time was 3 hours, how far away did her friend live?\r
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Algebra.Com's Answer #245032 by MathTherapy(10552)\"\" \"About 
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Ava rode her bike from her house to her friends house averaging 16 km per hour. It turned dark so her friend drove her home at a rate of 80 km per hour. If Ava's total traveling time was 3 hours, how far away did her friend live?\r
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\n" ); document.write( "\n" ); document.write( "For this problem, we need to reealize that since the total time for the roundtrip was 3 hours, then time to travel to her friend's house, plus time to return home equals 3. Using D as the distance, the speed to the friend's house, and the speed on the return trip, this is expressed as: \r
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\n" ); document.write( "\n" ); document.write( "\"D%2F16+%2B+D%2F80+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "Multiplying the equation by its LCD, 80, we get:\r
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\n" ); document.write( "\n" ); document.write( "5D + D = 240\r
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\n" ); document.write( "\n" ); document.write( "6D = 240\r
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\n" ); document.write( "\n" ); document.write( "D, or distance to friend's house = \"240%2F6\" or \"highlight_green%2840%29\" kilometers.
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