document.write( "Question 342300: While I can get the answer in a long handed table I am sure that a formula exists for this: From a group of six people, two individuals are to be selected at random. How many possible selections are there? \n" ); document.write( "
Algebra.Com's Answer #245030 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
This would be the combination formula of n! / (x! * (n-x)!) where:\r
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\n" ); document.write( "\n" ); document.write( "n = total number of people (6 in your case).\r
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\n" ); document.write( "\n" ); document.write( "x = number of people to be selected at one time (2 in your case).\r
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\n" ); document.write( "\n" ); document.write( "The formula for you becomes 6! / (2! * 4!) which becomes 6*5/2 which becomes 15.\r
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\n" ); document.write( "\n" ); document.write( "If we assume the people are abcdef, then the possible ocmbinations are:\r
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\n" ); document.write( "\n" ); document.write( "ab
\n" ); document.write( "ac
\n" ); document.write( "ad
\n" ); document.write( "ae
\n" ); document.write( "af
\n" ); document.write( "bc
\n" ); document.write( "bd
\n" ); document.write( "be
\n" ); document.write( "bf
\n" ); document.write( "cd
\n" ); document.write( "ce
\n" ); document.write( "cf
\n" ); document.write( "de
\n" ); document.write( "df
\n" ); document.write( "ef\r
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\n" ); document.write( "\n" ); document.write( "This assumes the order in which they are selected is not important.\r
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\n" ); document.write( "\n" ); document.write( "None of the sets has the same 2 people in them, regardless of order.\r
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