document.write( "Question 342200: Solve for equation: square root 2X-1 minus square root X-5 = 3 \r
\n" ); document.write( "\n" ); document.write( " not sure, will that be 2X times X and 2X times 5 - 1 times X and 1-5 under square root?
\n" ); document.write( "

Algebra.Com's Answer #245005 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%282x-1%29-sqrt%28x-5%29+=+3\"
\n" ); document.write( "\"sqrt%282x-1%29=sqrt%28x-5%29+%2B+3\"
\n" ); document.write( "Square both sides,
\n" ); document.write( "\"2x-1=%28x-5%29%2B6sqrt%28x-5%29%2B9\"
\n" ); document.write( "\"2x-1=%28x%2B4%29%2B6sqrt%28x-5%29\"
\n" ); document.write( "\"x-5=6sqrt%28x-5%29\"
\n" ); document.write( "Use a substitution, let \"u=x-5\"
\n" ); document.write( "\"u=6sqrt%28u%29\"
\n" ); document.write( "Square both sides,
\n" ); document.write( "\"u%5E2=36u\"
\n" ); document.write( "\"u%5E2-36u=0\"
\n" ); document.write( "\"u%28u-36%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"u=0\"
\n" ); document.write( "\"x-5=0\"
\n" ); document.write( "\"highlight%28x=5%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"u-36=0\"
\n" ); document.write( "\"u=36\"
\n" ); document.write( "\"x-5=36\"
\n" ); document.write( "\"highlight%28x=41%29\"
\n" ); document.write( "
\n" );