document.write( "Question 39077: Can someone out there help me with this problem?\r
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document.write( " How do you find the least common multiple (LCM) for the following group of numbers.
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document.write( " 12, 20, and 35. Explain if you can how you come up with your answer.
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document.write( " Thanks! \n" );
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Algebra.Com's Answer #24499 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! LCM OF 10,20 AND 35 \n" ); document.write( "LEAST COMMON MULTIPLE ..THAT IS THE SMALLEST NUMBER WHICH IS DIVISIBLE BY ALL THE 3 ABOVE NUMBERS .ONE METHOD IS TO BREAK THESE NUMBERS IN TO THEIR PRIME FACTORS.THAT IS \n" ); document.write( "TAKE 10...ITS FACTORS ARE 2*5 \n" ); document.write( "10=2*5.....................................I..SIMILARLY \n" ); document.write( "20=2*2*5...............................II \n" ); document.write( "35=5*7............................III \n" ); document.write( "NOW TO GET LCM ,WE LOOK FOR COMMON FACTORS IN ATLEAST 2 OF THE ABOVE EQNS.I,II,III \n" ); document.write( "WE FIND ONE 2 IS COMMON IN I&II \n" ); document.write( "AND ONE 5 IS COMMON IN I,II,III \n" ); document.write( "SO WE TAKE THOSE COMMON FACTORS,LIST THEM AND FIND THEIR PRODUCT.. \n" ); document.write( "LIST OF COMMON FACTORS.... \n" ); document.write( "2 AND 5. \n" ); document.write( "THEIR PRODUCT =PCF(PRODUCT OF COMMON FACTORS) \n" ); document.write( "2*5=10............................................IV \n" ); document.write( "NOW WE STRIKE OUT THE COMMON FACTORS AND WE LIST THE REMAINING \n" ); document.write( "NONE IN I(AS ONE 2 AND ONE 5 ARE LISTED IN COMMON FACTORS) \n" ); document.write( "2 IN II (AS ONLY ONE 2 AND ONE 5 ARE LISTED IN COMMON FACTORS) \n" ); document.write( "7 IN III(AS ONLY ONE 5 IS LISTED IN COMMON FACTORS) \n" ); document.write( "SO LIST OF NON COMMON FACTORS.. \n" ); document.write( "2 AND 7 \n" ); document.write( "THEIR PRODUCT = PNCF \n" ); document.write( "2*7=14............................................V \n" ); document.write( "NOW LCM IS GIVEN BY PRODUCT OF COMMON ANF NON COMMON FACTORS..IV AND V. \n" ); document.write( "LCM=10*14=140.. \n" ); document.write( " |