document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39078>Question 39078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "   Can you help me with this problem?  Add in the lowest terms:\r<BR>\n" );
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document.write( "       13/18 + 11/18  - Explain your answer in detail if you can.<BR>\n" );
document.write( "    Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24498 by </B><A HREF=/tutors/aboutme.mpl?userid=KneesAndToes><B>KneesAndToes(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KneesAndToes><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm not sure what you mean by add in lowest terms, but I saw this question was reposted, so I want to try and help.  I'm going to guess that it should just be the answer given in lowest terms, because the problem is already in lowest terms:<BR>\n" );
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document.write( "13/18 + 11/18 = ? ... (add numerators)<BR>\n" );
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document.write( "13/18 + 11/18 = 24/18<BR>\n" );
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document.write( "Now you will need to put this answer in lowest terms.  Unless common factors are obvious, I find it easiest to lower the numbers in steps.  In this problem, both the numerator and the denominator are divisible by two:<BR>\n" );
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document.write( "24/18 = 12/9<BR>\n" );
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document.write( "These numbers are both divisible by three:<BR>\n" );
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document.write( "4/3 - This is the answer in lowest terms.<BR>\n" );
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document.write( "I found this website... it looks like it may be helpful to you:<P><BR>\n" );
document.write( "<A HREF>http://www.helpwithfractions.com/index.html</A><BR>\n" );
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