document.write( "Question 342241: Use the quadratic formula to solve the equation for x in terms of y.?
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document.write( "2x^2 + 9xy -5 - y^2 = 0\r
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document.write( "This is what I did:
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document.write( "(2)x^2 + (9y)x + (-y^2-5) = 0
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document.write( "-9y +/- square root: 9y^2 -4(2)(-y^2-5) / 4
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document.write( "-9y +/- square root: 9y^2 + 8y^2 +40/ 4
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document.write( "-9y +/- square root : 17y^2 +40/ 4\r
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document.write( "Why is this answer wrong? Please explain. Thanks!! \n" );
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Algebra.Com's Answer #244972 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "You didn't square the \n" ); document.write( " \n" ); document.write( " |