document.write( "Question 342247: How many quarts of water must be added to 9 qt of an 80% antifreeze solution to make a 45% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #244913 by mananth(16946)\"\" \"About 
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let water required be x qt. 0%
\n" ); document.write( "9 qt 80%
\n" ); document.write( "Mixture = (x+9) qt 45%
\n" ); document.write( "..
\n" ); document.write( "9*0.8 = (x+9)*0.45
\n" ); document.write( "7.2=0.45x+4.05
\n" ); document.write( "0.45x=7.20-4.05
\n" ); document.write( "divide by 0.45
\n" ); document.write( "x= 3.15/0.45
\n" ); document.write( "x= 7 qt of water
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