document.write( "Question 342187: I have a new home 86 miles away. The movers left 12 minutes ago are traveling 50miles per hour I am leaving my house now and plan to drive 65 miles per hour. I want to reach the house before the movers, which means that I will pass them on the road. Create a system of equations to show the distance of the movers at any given time \n" ); document.write( "
Algebra.Com's Answer #244899 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Assume I have a stopwatch which I will start
\n" ); document.write( "when I leave house 12 min after movers.
\n" ); document.write( "My equation of motion is \"d%5B1%5D+=+65t\"
\n" ); document.write( "The equation for the movers is \"d%5B2%5D+=+50%2A%28t+%2B+12%2F60%29\"
\n" ); document.write( "Note that at \"t=0\" when the stopwatch starts
\n" ); document.write( "\"d=0\" for me, and \"d=10\" for movers
\n" ); document.write( "To find the time on stopwatch when I pass the movers,
\n" ); document.write( "set my \"d%5B1%5D\" equal to their \"d%5B2%5D\"
\n" ); document.write( "\"65t+=+50%2A%28t+%2B+1%2F5%29\"
\n" ); document.write( "\"65t+=+50t+%2B+10\"
\n" ); document.write( "\"15t+=+10\"
\n" ); document.write( "\"t+=+2%2F3\" hr
\n" ); document.write( "\"t+=+%282%2F3%29%2A60\" min
\n" ); document.write( "\"t+=+40\" min (time on stopwatch when I pass movers)
\n" ); document.write( "Here's a plot of the 2 equations:
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-1%2C+2%2C+-10%2C+100%2C+65x%2C+50x+%2B+10%29+\"
\n" ); document.write( "When \"d%5B1%5D+=+86\",
\n" ); document.write( " \"t+=+86%2F65\"
\n" ); document.write( "\"t+=+1.323\" hr
\n" ); document.write( "and \"d%5B2%5D+=+50%2A%281.323+%2B+.2%29\"
\n" ); document.write( "\"d%5B2%5D+=+76.15\" mi
\n" ); document.write( "\"86+-+76.15+=+9.85\" mi
\n" ); document.write( "This is how far behind the mover is when I reach house
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