document.write( "Question 342111: find the dimensions of a rectangle whose perimeter is 26 meters and are is 42 square meters \n" ); document.write( "
Algebra.Com's Answer #244865 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "26=2L+2W \n" ); document.write( "2L=26-2W \n" ); document.write( "L=(26-2W)/2 \n" ); document.write( "L=13-W \n" ); document.write( "A=LW \n" ); document.write( "42=(13-W)W \n" ); document.write( "42=13W-W^2 \n" ); document.write( "W^2-13W+42=0 \n" ); document.write( "(W-7)(W-6)=0 \n" ); document.write( "W-7=0 \n" ); document.write( "W=7 ANS \n" ); document.write( "L=13-7=6 ANS. \n" ); document.write( "W-6=0 \n" ); document.write( "W=6 ANS \n" ); document.write( "L=13-6=7 ANS. \n" ); document.write( "PROOF \n" ); document.write( "26=2*6+2*7 \n" ); document.write( "26=12+14 \n" ); document.write( "26=26 \n" ); document.write( "42=6*7 \n" ); document.write( "42=42 \n" ); document.write( " \n" ); document.write( " |