document.write( "Question 342111: find the dimensions of a rectangle whose perimeter is 26 meters and are is 42 square meters \n" ); document.write( "
Algebra.Com's Answer #244865 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
P=2L+2W
\n" ); document.write( "26=2L+2W
\n" ); document.write( "2L=26-2W
\n" ); document.write( "L=(26-2W)/2
\n" ); document.write( "L=13-W
\n" ); document.write( "A=LW
\n" ); document.write( "42=(13-W)W
\n" ); document.write( "42=13W-W^2
\n" ); document.write( "W^2-13W+42=0
\n" ); document.write( "(W-7)(W-6)=0
\n" ); document.write( "W-7=0
\n" ); document.write( "W=7 ANS
\n" ); document.write( "L=13-7=6 ANS.
\n" ); document.write( "W-6=0
\n" ); document.write( "W=6 ANS
\n" ); document.write( "L=13-6=7 ANS.
\n" ); document.write( "PROOF
\n" ); document.write( "26=2*6+2*7
\n" ); document.write( "26=12+14
\n" ); document.write( "26=26
\n" ); document.write( "42=6*7
\n" ); document.write( "42=42
\n" ); document.write( "
\n" ); document.write( "
\n" );