document.write( "Question 342107: How do you go about finding a pattern in a sequence of numbers? i just keep trying out different numbers but i just sit there for hours and some times i still don't see a pattern. Is there a process for finding a pattern? \n" ); document.write( "
Algebra.Com's Answer #244864 by stanbon(75887)\"\" \"About 
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How do you go about finding a pattern in a sequence of numbers? i just keep trying out different numbers but i just sit there for hours and some times i still don't see a pattern. Is there a process for finding a pattern?
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\n" ); document.write( "Assume you have a geometric sequence: 1,2,4,8,16,32,,,
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\n" ); document.write( "You are looking for a pattern to describe a(n) which is the nth term.
\n" ); document.write( "Start with
\n" ); document.write( "a(1) = 1
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\n" ); document.write( "Now a(2) is 2 but you are interested in finding the pattern
\n" ); document.write( "so you write
\n" ); document.write( "a(2) = 2*a(1)
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\n" ); document.write( "Now a(3) is 4 but you are interested in finding the pattern
\n" ); document.write( "so you write
\n" ); document.write( "a(3) = 2*a(2) = 2*2*a(1) = 2^2*a(1)
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\n" ); document.write( "Notice how you try to describe later numbers as related to an earlier number.
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\n" ); document.write( "a(4) = 2^3*a(1)
\n" ); document.write( "....
\n" ); document.write( "Keep this up as long as you have to till you see a pattern.
\n" ); document.write( "a(n) = 2^(n-1)*a(1)
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\n" ); document.write( "Now, a(1) is 1 in this problem so you can drop that
\n" ); document.write( "a(n) = 2^(n-1)
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\n" ); document.write( "Note: A sequence is a function with domain = 1,2,3,4,...,n
\n" ); document.write( "You are looking for a Rule for this function.
\n" ); document.write( "The Rule has to describe the y-value when n = 1 or 2 or 3, or simply n.\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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