document.write( "Question 342086: What is the reasoning behind the fact that it is not possible for the solution of an irrational number multiplied by a whole number (other than 0) to be a rational number? I know that it is not possible, which is the first step of the question, I just don't know the exact reasoning behind it. \n" ); document.write( "
Algebra.Com's Answer #244850 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let w = any whole number. We can write 'w' as \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, let i = any irrational number\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now assume that multiplying 'w' and 'i' will give you a rational number 'r'. We know it's false, but let's just hypothetically say that this is the case. We're basically looking for a contradiction which arises because of this assumption. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can represent 'r' by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now solve for 'i' to get \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So this means that the product of 'w' and 'i' is NOT rational. So it must be irrational (as it's the only other option)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, the product of a whole number and an irrational number is an irrational number.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( " |