document.write( "Question 342086: What is the reasoning behind the fact that it is not possible for the solution of an irrational number multiplied by a whole number (other than 0) to be a rational number? I know that it is not possible, which is the first step of the question, I just don't know the exact reasoning behind it. \n" ); document.write( "
Algebra.Com's Answer #244850 by jim_thompson5910(35256)\"\" \"About 
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Let w = any whole number. We can write 'w' as \"w%2F1\"\r
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\n" ); document.write( "\n" ); document.write( "Also, let i = any irrational number\r
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\n" ); document.write( "\n" ); document.write( "Now assume that multiplying 'w' and 'i' will give you a rational number 'r'. We know it's false, but let's just hypothetically say that this is the case. We're basically looking for a contradiction which arises because of this assumption. \r
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\n" ); document.write( "\n" ); document.write( "We can represent 'r' by \"r=a%2Fb\". So this means that \"wi=r\" and that \"wi=a%2Fb\". \r
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\n" ); document.write( "\n" ); document.write( "Now solve for 'i' to get \"i=a%2F%28bw%29\". Since \"a%2F%28bw%29\" is clearly a rational number, this means that 'i' is a rational number. But wait, we clearly stated that 'i' is an irrational number and it cannot be both. So we have a contradiction.\r
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\n" ); document.write( "\n" ); document.write( "So this means that the product of 'w' and 'i' is NOT rational. So it must be irrational (as it's the only other option)\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the product of a whole number and an irrational number is an irrational number.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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