document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=342062>Question 342062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please multiply\r<BR>\n" );
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document.write( "(-4n)^2(3n^7)^2\r<BR>\n" );
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document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244846 by </B><A HREF=/tutors/aboutme.mpl?userid=scottfin><B>scottfin(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scottfin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (-4n)^2 = (-4)(-4)=(16) square n =n^2. So one has (16n^2). Next,<BR>\n" );
document.write( "(3n^7)^2 = (3)(3)= (9) multiply your powers, ^7x^2=^14. So one has (9n^14). Next, put them together and multiply.<BR>\n" );
document.write( "(16n^2)(9n^14)<BR>\n" );
document.write( "16x9=144 and add powers 2^+14^=^16<BR>\n" );
document.write( "answer= 144n^16\r<BR>\n" );
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document.write( "(-4n)^2(3n^7)^2<BR>\n" );
document.write( "(16n^2)(9n^14)<BR>\n" );
document.write( "144n^16 </SPAN>\n" );
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