document.write( "Question 341951: Jody has a collection of 116 coins consisting of dimes, quarters, and silver dollars. The number of quarters is 5 less than three-fourths the number of dimes. The number of silver dollars is 7 more than five-eighths the number of dimes. How many coins of each kind are in her collection? \n" ); document.write( "
Algebra.Com's Answer #244818 by ankor@dixie-net.com(22740)\"\" \"About 
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Jody has a collection of 116 coins consisting of dimes, quarters, and silver dollars.
\n" ); document.write( "d + q + $ = 116
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\n" ); document.write( " The number of quarters is 5 less than three-fourths the number of dimes.
\n" ); document.write( "q = \"3%2F4\"d - 5
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\n" ); document.write( " The number of silver dollars is 7 more than five-eighths the number of dimes.
\n" ); document.write( "$ = \"5%2F8\"d + 7
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\n" ); document.write( "How many coins of each kind are in her collection?
\n" ); document.write( "Using the 1st equation replace q & $
\n" ); document.write( "d + \"3%2F4\"d - 5 + \"5%2F8\"d + 7 = 116
\n" ); document.write( "Common denominator
\n" ); document.write( "d + \"6%2F8\"d + \"5%2F8\"d + 2 = 116
\n" ); document.write( "d + \"11%2F8\"d = 116 - 2
\n" ); document.write( "d + \"11%2F8\"d = 114
\n" ); document.write( "Multiply by 8 to get rid of the denominator, results:
\n" ); document.write( "8d + 11d = 912
\n" ); document.write( "d = \"912%2F19\"
\n" ); document.write( "d = 48 dimes
\n" ); document.write( "then
\n" ); document.write( "q = \"3%2F4\"(48) - 5
\n" ); document.write( "q = 36 - 5
\n" ); document.write( "q = 31 quarters
\n" ); document.write( "and
\n" ); document.write( "$ = \"5%2F8\"(48) + 7
\n" ); document.write( "$ = 37 silver dollars
\n" ); document.write( ":
\n" ); document.write( "Check total: 48 + 31 + 37 = 116
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