document.write( "Question 341980: I know that the fomula x= -b/2a is used to solve for the minimum/maximum value of a quadratic formula but what happens when the quadratic formula is \"+y=+-6x%5E2-1+\" a= -6 b=0(?) c= -1. I know that the maximum value= -1 but I dont understand how to solve for it. Please Help Me. Thanks in advance for your help and glorious time.
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Algebra.Com's Answer #244814 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You are correct. The value of b is \"b=0\" since \"+y=+-6x%5E2-1+\" is the same as \"+y=+-6x%5E2%2B0x-1+\"\r
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\n" ); document.write( "\n" ); document.write( "So the x coordinate of the vertex is \"x=-b%2F2a=-0%2F%282%28-6%29%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "Plug this back in to get \"y=-6%280%29%5E2-1=-1\". So the vertex is (0, -1)\r
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\n" ); document.write( "\n" ); document.write( "So you are correct. The max value is -1.\r
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\n" ); document.write( "\n" ); document.write( "To solve \"+y=+-6x%5E2-1+\", plug in y=0 to get \"+0=+-6x%5E2-1+\"\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"-6x%5E2-1\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=-6\", \"B=0\", and \"C=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28%280%29+%2B-+sqrt%28+%280%29%5E2-4%28-6%29%28-1%29+%29%29%2F%282%28-6%29%29\" Plug in \"A=-6\", \"B=0\", and \"C=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+0-4%28-6%29%28-1%29+%29%29%2F%282%28-6%29%29\" Square \"0\" to get \"0\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+0-24+%29%29%2F%282%28-6%29%29\" Multiply \"4%28-6%29%28-1%29\" to get \"24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+-24+%29%29%2F%282%28-6%29%29\" Subtract \"24\" from \"0\" to get \"-24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+-24+%29%29%2F%28-12%29\" Multiply \"2\" and \"-6\" to get \"-12\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+2i%2Asqrt%286%29%29%2F%28-12%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280%2B2i%2Asqrt%286%29%29%2F%28-12%29\" or \"x+=+%28-0-2i%2Asqrt%286%29%29%2F%28-12%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-%28i%2Asqrt%286%29%29%2F%286%29\" or \"x+=+%28i%2Asqrt%286%29%29%2F%286%29\" Reduce and simplify\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+-%28i%2Asqrt%286%29%29%2F%286%29\" or \"x+=+%28i%2Asqrt%286%29%29%2F%286%29\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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