document.write( "Question 341888: a retangle has a area of 72 its length is twice its width what is its perimeter? \n" ); document.write( "
Algebra.Com's Answer #244783 by stanbon(75887)\"\" \"About 
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a retangle has a area of 72 its length is twice its width what is its perimeter?
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\n" ); document.write( "Area = length * width
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\n" ); document.write( "Let the width be \"w\"
\n" ); document.write( "Then the length is \"2w\"
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\n" ); document.write( "Solve with substitution:
\n" ); document.write( "72 = w*2w
\n" ); document.write( "36 = w^2
\n" ); document.write( "w = 6 units (width)
\n" ); document.write( "2w = 12 units (length)
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\n" ); document.write( "Now, determine the perimeter.
\n" ); document.write( "P = 2(L+W)
\n" ); document.write( "P = 2(12+6)
\n" ); document.write( "P = 2(18)
\n" ); document.write( "Perimeter = 36 units
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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