document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341890>Question 341890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a retangle has a area of 72 its length is twice its width what is its perimeter?\r<BR>\n" );
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document.write( "please sent me the anwser!!!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244782 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a area of 72.<BR>\n" );
document.write( "its length is twice its width what is its perimeter?<BR>\n" );
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document.write( "Let the width be W.<BR>\n" );
document.write( "Then the length is 2W.<BR>\n" );
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document.write( "Formula: Perimeter = 2(Length + Width)<BR>\n" );
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document.write( "Solve by substituting:<BR>\n" );
document.write( "72 = 2(2W+W)<BR>\n" );
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document.write( "36 = 3W<BR>\n" );
document.write( "w = 12 units (width) <BR>\n" );
document.write( "2w = 24 units (length)<BR>\n" );
document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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