document.write( "Question 341835: Walt made an extra $9000.00 last year from a part time job. He invested part of the money at 8% and the rest at 7%. He made a total of $680.00 in nterest. How much was invested? \n" ); document.write( "
Algebra.Com's Answer #244767 by mananth(16946)\"\" \"About 
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let him invest $x at 8%
\n" ); document.write( "he will invest 9000-x at 7%
\n" ); document.write( "he recieved an interest of $680
\n" ); document.write( "..
\n" ); document.write( "0.08x+0.07(9000-x)=680
\n" ); document.write( "multiply by 100
\n" ); document.write( "8x+7(9000-x)=100*680
\n" ); document.write( "8x+63000-7x= 68000
\n" ); document.write( "x= 68000-63000
\n" ); document.write( "x= 5000 amount invested @ 8%
\n" ); document.write( "balance $4000 he invests at 7%
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