document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341841>Question 341841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is three times as old as her daughter. Nine years ago, she was six times as old a her daughter. Find the present age of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244746 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let daughter be x years now<BR>\n" );
document.write( "mother is 3x now.<BR>\n" );
document.write( "9 years ago<BR>\n" );
document.write( "daughter = x-9<BR>\n" );
document.write( "mother = 3x-9<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x-9 = 6(x-9)<BR>\n" );
document.write( "3x-9 = 6x -54<BR>\n" );
document.write( "6x-3x= 54 -9<BR>\n" );
document.write( "3x=45<BR>\n" );
document.write( "divide by 3<BR>\n" );
document.write( "x= 15 daughter's age<BR>\n" );
document.write( "mother's age = 3x = 3*15 = 45 years </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );