document.write( "Question 341826: This problem involves factoring terms that include positive and negative exponents. For some reason I just can't see it:\r
\n" ); document.write( "\n" ); document.write( "(3x+2)(2/3)(6x-5)^(-1/3)(6)+(6x-5)^(2/3)(3)\r
\n" ); document.write( "\n" ); document.write( "I keep coming up with:
\n" ); document.write( "I factored out (6x-5)^(-1/3)(2/3)(3)[(3x+2)+2(6x-5)^(3/3) <- (or 1)
\n" ); document.write( "So that simplifies to: (6x-5)^(-1/3)(2)(3x+2)+12x-10
\n" ); document.write( "Further simplified to: (6x-5)^(-1/3)[6x+4+12x-10]
\n" ); document.write( "The (6x-5)^(-1/3) moves to the denominator and 18x-6 remains in the numerator. \r
\n" ); document.write( "\n" ); document.write( "I don't know where I am going wrong with this. I know the denominator is right, but the answer shown for the numerator is 30x-7 and I just can't figure out how to get to that.
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Algebra.Com's Answer #244741 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(3x+2)(2/3)(6x-5)^(-1/3)(6)+(6x-5)^(2/3)(3)
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\n" ); document.write( "[4(3x+2)*(6x-5)^(-1/3)] + [3(6x-5)^(2/3)]
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\n" ); document.write( "Common Factor: (6x-5)^(-1/3)
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\n" ); document.write( "= CF[12x+8 + 3(6x-5)]
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\n" ); document.write( "= CF[12x+8+18x-15]
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\n" ); document.write( "= CF[30x-7]
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\n" ); document.write( "= [30x-7]/(6x-5)^(1/3)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( " I know the denominator is right, but the answer shown for the numerator is 30x-7 and I just can't figure out how to get to that.
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