document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341788>Question 341788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if manufacture of 5 cm screws , the screw is rejected if the diameter of the screw is outside 0.05% of the designed value .in long run, 1 in every 100 screw is found to be defective . if a test sample of 10 screws is taken , find the probabilities of ;<BR>\n" );
document.write( "a- no defective<BR>\n" );
document.write( "b- not more than one defective <BR>\n" );
document.write( "c- at least one difective  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244728 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a+b)^10=a^10+10a^9b+... Let a=.99 and b=.01<BR>\n" );
document.write( "We don't need to go any farther with the expansion for this problem.<BR>\n" );
document.write( "a) .99^10=.9043 None defective.<BR>\n" );
document.write( "c) 1-.9043=.0956 at least one defective.<BR>\n" );
document.write( "b) <BR>\n" );
document.write( "10*0.99^9*0.01=.0914 exactly one defective.<BR>\n" );
document.write( ".9043+.0914=.9957 not more than 1 defective<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );