document.write( "Question 341706: The length of a rectangle is 4 inches more than twice the width. The perimeter is 68 cm. Find the dimensions of the rectange. (Round to two decimal places.) \n" ); document.write( "
Algebra.Com's Answer #244696 by Jeannie1012(8)![]() ![]() You can put this solution on YOUR website! To solve the perimeter of a rectangle you will use the formula 2W + 2L = perimter\r \n" ); document.write( "\n" ); document.write( "First: Draw a picture of a rectangle. Label the width w since you don't know its value. Now for the length you know that it is 4 inches more than 2 times the width or 2w + 4\r \n" ); document.write( "\n" ); document.write( "so we know that: \n" ); document.write( "width = W \n" ); document.write( "Length = 2W + 4 \n" ); document.write( "perimeter = 68\r \n" ); document.write( "\n" ); document.write( "STEP 2: plug the values you have into the formula. So 2L + 2w = perimeter becomes \n" ); document.write( " 2(2w+4) + 2w = 68\r \n" ); document.write( "\n" ); document.write( "STEP 3: Use distribution to solve and you get 4w + 8 + 2w = 68 \n" ); document.write( "STEP 4: combine like terms and you get 6W + 8 = 68 \n" ); document.write( "STEP 5: subtract 8 from both sides to get 6w alone and you get 6w = 60 \n" ); document.write( "STEP 6: Divide by 6 to get the w alone, don't for get what you do to one side you have to do to the other so 6w/6 = w and 60 /6 = 10 \n" ); document.write( "and we now know that W = 10\r \n" ); document.write( "\n" ); document.write( "now you can check your work by plugging 10 into the equation anywhere there is a w. so for length 2w + 4 become 2(10) + 4 = 20 + 4 \n" ); document.write( "L = 24 \n" ); document.write( "and W = 10 \n" ); document.write( "so 2L + 2W = 68 becomes \n" ); document.write( "2(24) +2(10) = 68 \n" ); document.write( "48 + 20 = 68 \n" ); document.write( "68 = 68 so it checks. \n" ); document.write( " |