document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341752>Question 341752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am checking my answer to the following (the answer is not in the book):\r<BR>\n" );
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document.write( "A solution is 30% chlorine and another solution is 70% chlorine.  How many liters of each solution should you use to make 150 liters of a solution that is 55% chlorine?\r<BR>\n" );
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document.write( "I wrote the equation like this:<BR>\n" );
document.write( ".3x + .7(150-x)= .55(150)\r<BR>\n" );
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document.write( "I broke this down to x=56.25\r<BR>\n" );
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document.write( "56.25 Liters of 30% solution and 93.75 liters of 70% solution<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244666 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A solution is 30% chlorine and another solution is 70% chlorine. How many liters of each solution should you use to make 150 liters of a solution that is 55% chlorine? <BR>\n" );
document.write( "I wrote the equation like this:<BR>\n" );
document.write( ".3x + .7(150-x)= .55(150) <BR>\n" );
document.write( "I broke this down to x=56.25 <BR>\n" );
document.write( "56.25 Liters of 30% solution and 93.75 liters of 70% solution<BR>\n" );
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document.write( "That is correct.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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