document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341496>Question 341496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if one leg of a right triangle is 14 meters shorter than the other leg, and the hypotenuse is 26 meters, find the length of the two legs.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244558 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if one leg of a right triangle is 14 meters shorter than the other leg, and the hypotenuse is 26 meters, find the length of the two legs.<BR>\n" );
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document.write( "Let one of the legs have length x.<BR>\n" );
document.write( "Then the other leg's length is x-14.<BR>\n" );
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document.write( "Using Pythagoras you get:<BR>\n" );
document.write( "26^2 = x^2 + (x-14)^2<BR>\n" );
document.write( "x^2 + x^2-28x+196 = 676<BR>\n" );
document.write( "2x^2 -28x -480 = 0<BR>\n" );
document.write( "x^2 -14x -240 = 0<BR>\n" );
document.write( "(x-24)(x+10) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 24 meters (longer leg)<BR>\n" );
document.write( "x-14 = 10 meters (shorter leg)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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