document.write( "Question 341326: John is 13 years less than 3 times as old as his son. Six years ago, he was 14 years more than twice as old as his son was then. How old is John? \n" ); document.write( "
Algebra.Com's Answer #244536 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! John is 13 years less than 3 times as old as his son. \n" ); document.write( " Six years ago, he was 14 years more than twice as old as his son was then. \n" ); document.write( " How old is John? \n" ); document.write( ": \n" ); document.write( "Let j = John's present age \n" ); document.write( "Let s = son's present age \n" ); document.write( ": \n" ); document.write( "Write a equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"John is 13 years less than 3 times as old as his son.\" \n" ); document.write( "j = 3s - 13 \n" ); document.write( "; \n" ); document.write( "\" Six years ago, he was 14 years more than twice as old as his son was then.\" \n" ); document.write( "j - 6 = 2(s-6) + 14 \n" ); document.write( "j - 6 = 2s - 12 + 14 \n" ); document.write( "j - 6 = 2s + 2 \n" ); document.write( "j = 2s + 2 + 6 \n" ); document.write( "j = 2s + 8 \n" ); document.write( ": \n" ); document.write( "Replace j with (3s-13) from the 1st statement: \n" ); document.write( "3s - 13 = 2s + 8 \n" ); document.write( "3s - 2s = 8 + 13 \n" ); document.write( "s = 21 yrs is the son's age \n" ); document.write( ": \n" ); document.write( "How old is John? j = 3s - 13 \n" ); document.write( "j = 3(21) - 13 \n" ); document.write( "j = 63 - 13 \n" ); document.write( "j = 50 yrs is John's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the statement: \n" ); document.write( "\"Six years ago, he was 14 years more than twice as old as his son was then. \" \n" ); document.write( "50 - 6 = 2(21 - 6) + 14 \n" ); document.write( "44 = 2(15) + 14; confirms our solution \n" ); document.write( " |