document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38989>Question 38989</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man has five sons, each three years older than the next younger. The age of the oldest in three years will be three times the present age of the second youngest. How old is each son from youngest to oldest?\r<BR>\n" );
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document.write( "(Not from a text) seems simple. Would the youngest be 3 and the oldest 15?<BR>\n" );
document.write( "Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24441 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24441\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 sons --> x, x+3, x+6, x+9, x+12<BR>\n" );
document.write( "Age of the oldest in 3 years = x+12+3=x+15<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x+15=3(x+3)<BR>\n" );
document.write( "x+15=3x+9<BR>\n" );
document.write( "-2x=-6<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "Hence, the yougest son is 3 (add 3 to each of the other sons ages)<BR>\n" );
document.write( "Paul. </SPAN>\n" );
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