document.write( "Question 38989: A man has five sons, each three years older than the next younger. The age of the oldest in three years will be three times the present age of the second youngest. How old is each son from youngest to oldest?\r
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Algebra.Com's Answer #24440 by checkley71(8403)\"\" \"About 
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YES. (X+3)*3=(X+12)+3 OR 3X+9=X+15 OR 2X=6 OR X=3 THUS THE YOPUNGEST IS 3 YEARS OLD THE SECOND YOUNGEST IS 6 AND THE OLDEST IS 15 THUS WE HAVE 3,6,9,12&15 & IN 3 YEARS THE OLDEST WILL BE 18 WHICH IS 3*6=18. \n" ); document.write( "
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