document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341315>Question 341315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 27 pounds of feed worth $0.26 per pound by mixing one kind worth $0.17 per pound with another worth $0.36 per pound. How many pounds of the cheaper kind should they use in the mix?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244399 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one kind worth $0.17 per pound let this be x lbs.<BR>\n" );
document.write( "with another worth $0.36 per pound. this will be 27-x lbs<BR>\n" );
document.write( "27 pounds $0.26 per pound <BR>\n" );
document.write( "..<BR>\n" );
document.write( "0.17*x+0.36(27-x)=27*0.26<BR>\n" );
document.write( "0.17x+9.72-0.36x= 7.02<BR>\n" );
document.write( "-0.19x = -9.72+7.02<BR>\n" );
document.write( "-0.19x=-2.70<BR>\n" );
document.write( "x= -2.70/-0.19<BR>\n" );
document.write( "= 14.2 lbs. </SPAN>\n" );
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