document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341313>Question 341313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I answer this problem, The width of the triangle is one-third of the length. If the perimeter is 40 cm, find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244398 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter formula is:\r<BR>\n" );
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document.write( "P = 2w + 2L\r<BR>\n" );
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document.write( "The width is: w = L/3\r<BR>\n" );
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document.write( "So take the w =L/3 and substitute it into the perimeter formula:\r<BR>\n" );
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document.write( "P = 2w + 2L<BR>\n" );
document.write( "40 = 2(L/3) + 2L<BR>\n" );
document.write( "40 = 2L/3 + 2L<BR>\n" );
document.write( "40 = 2L/3 + 6L/3<BR>\n" );
document.write( "40 = 8L/3<BR>\n" );
document.write( "120 = 8L<BR>\n" );
document.write( "L = 15\r<BR>\n" );
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document.write( "So length = 15 cm.\r<BR>\n" );
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document.write( "Width = Length/3<BR>\n" );
document.write( "Width = 15/3 = 5 cm. </SPAN>\n" );
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