document.write( "Question 341308: Jill is 27.5 kilometers away from Joe. Both begin to walk toward each other at thre same time. Jill walks at 3 kilometers per hour. They meet in 5 hours. How fast is Joe walking? \n" ); document.write( "
Algebra.Com's Answer #244396 by texttutoring(324) You can put this solution on YOUR website! They meet in 5 hours, and Jill walks at 3 km/hr. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to use the formula D=VT, where D=distance, V=velocity (or speed) and T=time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jill:\r \n" ); document.write( "\n" ); document.write( "D=VT \n" ); document.write( "D=(3)(5) \n" ); document.write( "D=15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So Jill travelled 15 km.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jill and Joe started 27.5 km apart, which means that Joe must have travelled 27.5-15 = 12.5 km. We know he also walked for 5 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for V in the Joe equation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "V = D/T \n" ); document.write( "V = 12.5 / 5 \n" ); document.write( "V = 2.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So Joe is walking 2.5 km/h. \n" ); document.write( " |