document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341276>Question 341276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The longest side of a triangle is twice as long as the shortest side and the remaining side is 25. If the perimeter is 70, find the lengths of the sides of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244391 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let L=longest, s=shortest, m=remaining side's length.<BR>\n" );
document.write( "L=2s<BR>\n" );
document.write( "m=25<BR>\n" );
document.write( "s+2s+25=70<BR>\n" );
document.write( "3s+25=70<BR>\n" );
document.write( "3s=45<BR>\n" );
document.write( "s=15<BR>\n" );
document.write( "L=30<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );