document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341285>Question 341285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angle a is 1/2 as large as its complement angle b, find the measue of each angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244374 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244374\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Complementary angels add to 90 degrees...so<BR>\n" );
document.write( "a + b = 90<BR>\n" );
document.write( "and we also have<BR>\n" );
document.write( "a = 1/2 b<BR>\n" );
document.write( "now substitute and get<BR>\n" );
document.write( "1/2 b + b = 90<BR>\n" );
document.write( "3/2 b = 90<BR>\n" );
document.write( "multiply by 2/3<BR>\n" );
document.write( "b = 60<BR>\n" );
document.write( "a = 30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );