document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341183>Question 341183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two times the least of three consecutive odd integers exceeds three times the greatest by 15. What are the integeres?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244372 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the least of the three integers x.  The next odd one is two more or x + 2, and the next is x + 4.<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "2x - 15 = 3(x + 4)<BR>\n" );
document.write( "We subtract the 15 since it exceeds three times the largest...so,<BR>\n" );
document.write( "2x - 15 = 3x + 12<BR>\n" );
document.write( "subtract 2x from both sides and then subtract 12...<BR>\n" );
document.write( "-15 = x + 12<BR>\n" );
document.write( "-27 = x<BR>\n" );
document.write( "The numbers are -27, -25, and -23.<BR>\n" );
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