document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341277>Question 341277</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plane flies south for 2 hours and 30 minutes at a speed of 400 kilometers/hour. Then it turns and flies east for 1 hour and 45 minutes at a speed of 420 kilometer/hour. What is the plane's displacement from its initial position? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244368 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to draw a triangle. One arm goes south, the other arm points east.\r<BR>\n" );
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document.write( "use the formula D=VT, where D=distance, V=velocity (speed) and T=time\r<BR>\n" );
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document.write( "Convert the times to hours with decimals (i.e. 2 hours and 30 minutes is the same thing as 2.5 hours)\r<BR>\n" );
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document.write( "South: D = (400)(2.5) = 1000 km<BR>\n" );
document.write( "East: D = (420)(1.75) = 735 km\r<BR>\n" );
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document.write( "Now you should do Pythagorean theorem with 1000 as one arm, and 735 as the other arm.\r<BR>\n" );
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document.write( "Let the displacement = x\r<BR>\n" );
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document.write( "x^2 = 1000^2 + 735^2<BR>\n" );
document.write( "x = 1241\r<BR>\n" );
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document.write( "So the plane is 1241 km away from where it started (as measured along the diagonal line). </SPAN>\n" );
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