document.write( "Question 341132: 6. A force of 55 Newtons is acting on a body in a north direction. A second force of 30 Newtons is applied to the body in a south direction. What is the net force and direction of action?
\n" ); document.write( "55-30= 25 Newtons in a north direction \r
\n" ); document.write( "\n" ); document.write( "8. Use the data in problem 6, only this time the second force acts in an east direction. What is the net force and direction of action. \r
\n" ); document.write( "\n" ); document.write( "I got number 6 answered, but i'm having trouble with number 8.
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Algebra.Com's Answer #244354 by Fombitz(32388)\"\" \"About 
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The magnitude of the \"F\" is obtained by,
\n" ); document.write( "\"F%5E2=55%5E2%2B30%5E2\"
\n" ); document.write( "\"F%5E2=3025%2B900\"
\n" ); document.write( "\"F%5E2=3925\"
\n" ); document.write( "\"F=62.6\" N
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\n" ); document.write( "\"tan%28theta%29=55%2F30\"
\n" ); document.write( "\"tan%28theta%29=1.83\"
\n" ); document.write( "\"theta=61.4\"degrees, North of East.
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