document.write( "Question 341257: Write the equation in slope-intercept form of the line passing through the point P(2,-7) and the perpendicular to 5x+27=18. \r
\n" ); document.write( "\n" ); document.write( " the answer my teacher gave us is Y=2/5x-39/5 . I got the 2/5x by solving for y what i dont understand is how she got 39/5. i keep going over to see if i have forgotten some part of the problem but i just dont see where i made the mistake
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Algebra.Com's Answer #244333 by Alan3354(69443)\"\" \"About 
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Write the equation in slope-intercept form of the line passing through the point P(2,-7) and the perpendicular to 5x+27=18.
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\n" ); document.write( "I think you mean 5x + 2y = 18, judging from the slope.
\n" ); document.write( "Find the slope:
\n" ); document.write( "m = -5/2
\n" ); document.write( "The slope of lines perpendicular are the neg inverse, = +2/5
\n" ); document.write( "Use y = mx + b and the point to find b
\n" ); document.write( "-7 = (2/5)*2 + b
\n" ); document.write( "b = -7 - 4/5
\n" ); document.write( "b = -39/5
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\n" ); document.write( "y = (2/5)x - 39/5
\n" ); document.write( "The teacher is always right. Most of the time.
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