document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341251>Question 341251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x+3=-2x-12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244323 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+3=-2x-12\r<BR>\n" );
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document.write( "Let's get all the x terms on the left side, and the numbers on the right.\r<BR>\n" );
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document.write( "Add 2x to both sides:\r<BR>\n" );
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document.write( "3x+3+2x=-2x-12+2x<BR>\n" );
document.write( "5x+3 = -12\r<BR>\n" );
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document.write( "Subtract 3 from both sides:<BR>\n" );
document.write( "5x+3-3 = -12-3<BR>\n" );
document.write( "5x = -15\r<BR>\n" );
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document.write( "Divide both sides by 5:\r<BR>\n" );
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document.write( "5x/5 = -15/5<BR>\n" );
document.write( "x = -3\r<BR>\n" );
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document.write( "So x= -3. </SPAN>\n" );
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